Name:
Muhammad Shahbaz Sharif

Student
Id: Bc160401593

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Assignment
No. 3

                                                            PHY
(101)

Question
# 1

A video game console operates potential difference
of 12.00 V as shown in fig. The potential difference supplied by the power
receptacle is 120 V AC. A transformer is used to convert one voltage to the
other. If the secondary coil of the transformer (the 12.00 V side) has 1200
loops, how many loops does the primary coil have?

 

 

 

Solution:

Within a magnetic core magnetic flux occurs. The
flux dependent on primary current and primary turns Ip*Np. This same flux flows
in the core of secondary Is*Ns,

So Ip*Np= Is*Ns

Now on voltage, in accordance with lenz’s law, this
flux causes in each turn, an induced voltage. So the total include voltage is k*voltage/turn*turns*flux

Vs=kNs*flux

Or Vs/Ns=k*flux. But on the primary, the same
constant k is occurring in generating the flux, so

Vs/Ns=Vp/Np

Or VpVs=NpNs

120/12=1200/Ns

Or    Ns=12000 turns.

Question # 2

a)      Is it true or wrong to say that components in series must have the same
potential difference across them? Either yes or no explain it.                                          

b)      Is it true or wrong to say that magnetic
force vectors on charged particles point in the same direction as the magnetic
field? Either yes or no explain it.                                

c)      What is the
electric potential at the location of the test charge in the figure shown below?      

                                                                                                       

Solution:

a)     
When two or more components are
connected in series, the potential difference of the supply is shared between
them. This mean that if you add together the voltage across each component
connected in series, the total equals the voltage of the power supply. Two
identical resistors connected in series will share the potential difference.
They will get half to each.

For example: If two identical resistors
are connected in series to 3V cell then the potential difference across each of
them is 1.5V.

b)    
When a charged particle moved
through a magnetic field B, it feels a Force F given by cross product is F=qV*B
where is the electric charge of the particle is the magnetic field because this
is across product, the force is perpendicular to both the motion of the
particular and the magnetic field. It follows that the magnetic force does not
work on the particle it may change the direction of the particle movement, but
it cannot cause it to speed up or slow down.

c)     
Clearly, the potential Function V
can be assigned to each point in the space surrounding a charge distribution.
The above formula provide the recipe to calculate the work done in moving a
charge between two points where we know that the value of the potential
differences.

The above statements and the
formula are valid regardless of the path through which the formulas are valid
regardless of the path through which the charged is moved. It can be found by
simple performance the integration through a simple path is chosen along a
radial line so that becomes simply. Since the electric field of Q is Kq/r2.
This process defines the electric potential of a point like charge. Note that
the potential function is a Scalar Quantity as oppose to electric field are
Vector Quantity.

 

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